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A soccer player kicks a 0.5 kilogram ball with a force of 50 Newton’s.what is the force of the players foot

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Answer:

The force acting on the player's foot is, -50 N

Step-by-step explanation:

Given data,

The mass of the football, m = 0.5 kg

The soccer player kicks with a force of, F = 50 N

According to newton's III law of motion, Whenever a body exerts a force on an object, the object exerts the same magnitude of force on the body, but in the opposite direction.

According to the law,

F₁ = -F₂

Where

F₁ is the action force

F₂ is the reaction force

Hence, the force acting on the players's foot is F₂ = -50 N

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User DACrosby
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