Question

Help please and show work!!

Answer 1

3) OPTION 4

4) OPTION 1

Explanation:

3) Mean is the usual average.

Here, the data is: 60, 74, 82, 87, 87, 94.

Mean =
`$ (60 + 74 + 82 + 87 + 87 + 94)/(6) $`

`$ = (484)/(6) $` = 80.667

Median: For even number of terms, Median =
`$ \frac{ ((n)/(2))^(th) \hspace{2mm}term + ((n)/(2) + 1)^(th) \hspace{2mm} term}{2} $`

Before using the formula we arrange the data in the size of increasing order.

`$ \implies 60, 74, 82, 87, 87, 94 $`

So, since there are even terms here,
`$ ((n)/(2))^(th)$` term is 82 and
`$ ((n)/(2) + 1)^(th) $` term is 87, we have,

Median =
`$ (82 + 87)/(2) $`

= 84.5

Mode is the value with highest frequency in the data.

Here, 87 has occurred with frequency 2.

Therefore, Mode = 87

4) Data: 5, 5, 7, 7, 6

Mean =
`$ (5 + 5 + 7 + 7+ 6)/(5) $`

= 6

Median: When the data set has odd numbers. It is the center term.

After arranging the terms in increasing order, the center term is 6.

So, Median = 6.

Mode: Terms with high frequency.

Here, both 5 and 7 occur with frequency 2, Mode = 5, 7.