Question

A 175-kg motorcycle goes around an unbanked turn of radius 75.4 m at a steady 112 km/h. Determine its acceleration?

Answer

Answer 1

Answer:
`12.83 m/s^(2)`

Step-by-step explanation:

In this case we are talking about the centripetal acceleration
`a_(c)`, which can be calculated by:

`a_(c)=(V^(2))/(r)`

Where:

`V=112 (km)/(h) (1000 m)/(1 km) (1h)/(3600 s)=31.11 m/s` is the speed of the motorcycle

`r=75.4 m` is the radius of the path the motorcycle is going around

Solving:

`a_(c)=((31.11 m.s)^(2))/(75.4 m)`

Finally:

`a_(c)=12.83 m/s^(2)`