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Solve (x + 2 < 5) ∩ (x - 7 > -6). 1 < x < 3 x < 3 or x > 1 {all real numbers}

Solve (x + 2 < 5) ∩ (x - 7 > -6). 1 < x < 3 x < 3 or x > 1 {all real numbers}
asked 5.1k views
1 vote
Solve (x + 2 < 5) ∩ (x - 7 > -6).

1 < x < 3
x
{all real numbers}

asked
User Sancho Panza
by
8.3k points

2 Answers

0 votes

Answer:

B(2)

Explanation:

answered
User Archlight
by
8.4k points
4 votes

Answer:

the correct answer is B(2)

Explanation:

answered
User Clint Good
by
8.4k points
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