asked 136k views
5 votes
A farmer wants to test the effectiveness of a pest control method in allowing strawberry blooms to yield marketable strawberries. Of a random sample of 100 blooms, 77 yield marketable strawberries. Is this evidence that two thirds or more of all blooms grown with this pest control method end up as marketable strawberries? The value of the z statistic for this test is about?

a. z = 2.46
b. z = 1.03
c. z = 2.19

asked
User Abhay PS
by
8.1k points

1 Answer

6 votes

Answer:

Option C is right.

Explanation:

Given that a farmer wants to test the effectiveness of a pest control method in allowing strawberry blooms to yield marketable strawberries.

Samplesize = 100

Favorable =77

Sample proportion p = 0.77


H_0: p =2/3 =0.667\\H_a: p >0.667

(Right tailed test)

Assuming H0 to be true,

Standard error of proportion p =
\sqrt{(0.667*0.333)/(100) } \\=0.04713

p difference = 0.103

Test statistic Z = p difference/std error = 2.186

=2.19

Option C is right

answered
User Mehdi Yeganeh
by
7.9k points
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