Question

Many species cool themselves by sweating, because as the sweat evaporates, heat is transferred to the surroundings. A human exercising strenuously has an evaporative heat loss rate of about 657 W. If a person exercises strenuously for 28.6 min, how much water must he drink to replenish his fluid loss? The heat of vaporization of water is 2430 J/g at normal skin temperature.

Answer 1

The water lost is 463.95 g.

Step-by-step explanation:

Given that,

Heat lost rate = 657 W

Time = 28.6 min

Heat vaporization = 2430 J/g

We need to calculate the heat lost

Using formula of heat loss

`heat\ lost =657*28.6*60`

`heat\ lost=1127412\ J`

We need to calculate the water lost

Using formula of water lost

`water\ lost=(heat\ lost)/(heat\ vaporization)`

Put the value into the formula

`water\ lost=(1127412)/(2430)`

`water\ lost=463.95\ g`

Hence, The water lost is 463.95 g.