What is the equation of a line parallel to y=3x+1 that passes through the point at (-2,-4)? Oy=3x + 4 Dy=3x – 4 y=3x + 2 y= 3x - 2 Pleaseee help!!!

Question

asked Jan 17, 2020 161k views

1 Answer

Daniel Delaney · Answer 1 · 2020-01-23T03:20:56+0000

Answer:

Explanation:

Given equation:

y=3x+1

To find the equation of line parallel to the line of the given equation and passes through point (-2,4).

Applying slope relationship between parallel lines.

where
and
are slopes of parallel lines.

For the given equation in the form
y=mx+b the slope
m_2 can be found by comparing
y=3x+1 with standard form.

∴
m_2=3

∴
m_1=3

The line passes through point (-2,4)

Using point slope form:

y_-y_1=m(x_-x_1)

Where
$(x_1,y_1)\rightarrow (-2,4)$ and
m=m_1=3

So,

y-(-4)=3(x-(-2))

Simplifying

y+4=3(x+2)

Using distribution.

y+4=(3x)+(2* 3)

y+4=3x+6

Subtracting 4 from both sides.

y+4-4=3x+6-4

y=3x+2

Thus the equation of line in standard form is given by:

(Answer)