Question

Formula units in 0.0300 moles of cacl2

Answer 1

no of formula unit =
`0.03* 6.023* 10^(23)=1.8* 10^(22)`

Step-by-step explanation:

atomic mass of CaCl2 = 40 + 2×35.5 = 111 g.

no of formula unit = no of moles × Avagadro number

=
`0.03* 6.023* 10^(23)=1.8* 10^(22)`