Answer:
Explanation:
The attached diagram shows the given triangle labelled as triangle ABC. Line DE is parallel to line AB. It means that triangle DEC is similar to triangle ABC. Comparing the sides,
DC/DE = AC/AB
DC = 5
DE = 8
AC = 5 + x
AB = 10
Therefore,
5/8 = (5+x)/10
Cross multiplying
5 × 10 = 8(5 + x)
50 = 40 + 8x
8x = 50-40 = 10
x = 10/8 = 1.25
Similarly,
CE/DE = CB/AB
CE = 7
CB = 7 + y
DE = 8
AB = 10
Therefore
7/8 = (7+y)/10
Cross multiplying
7 × 10 = 8(7 + y)
70 = 56 + 8y
8y = 70 - 56 = 14
y = 14/8 = 1.75