Question

What is the equation for a line passing through (-2,3) and perpendicular to y= -1/2+1 ?

Answer 1

`y=2x+7`

Explanation:

The correct question is

what is the equation for a line passing through (-2,3) and perpendicular to y= -1/2x+1 ?

Remember

If two lines are perpendicular, then their slopes are opposite reciprocal (the product of their slopes are equal to -1)

The slope of the given line is m=-1/2

so

the opposite reciprocal is m=2

Find the equation of the line in point slope form

`y-y1=m(x-x1)`

we have

`m=2\\point\ (-2,3)`

substitute

`y-3=2(x+2)`

Convert to slope intercept form

`y=mx+b`

isolate the variable y

`y-3=2x+4`

`y=2x+4+3`

`y=2x+7`