Question

The star Rho1 Cancri is 57 light-years from the earth and has a mass 0.85 times that of our sun. A planet has been detected in a circular orbit around Rho1 Cancri with an orbital radius equal to 0.11 times the radius of the earth's orbit around the sun.What are

(a) the orbital speed
(b) the orbital period of the planet of Rho' Cancri?

Answer 1

82780.42123 m/s

14.45 days

Step-by-step explanation:

m = Mass of the planet

M = Mass of the star =
`0.85* 1.989* 10^(30)\ kg=1.69065* 10^(30)\ kg`

r = Radius of orbit of planet =
`0.11* 149.6* 10^(9)\ m=16.456* 10^(9)\ m`

v = Orbital speed

The kinetic and potential energy balance of the planet and star system is given by

`(GMm)/(r^2)=(mv^2)/(r)\\\Rightarrow v=\sqrt{(Gm)/(r)}\\\Rightarrow v=\sqrt{(6.67* 10^(-11)* 1.69065* 10^(30))/(16.456* 10^(9))}\\\Rightarrow v=82780.42123\ m/s`

The orbital speed is 82780.42123 m/s

The orbital period is given by

`t=(2\pi r)/(v)\\\Rightarrow t=(2\pi * 16.456* 10^(9))/(82780.42123)\\\Rightarrow t=1249040.48419\ seconds`

Converting to days

`(1249040.48419)/(24* 60* 60)=14.45\ days`

The orbital period is 14.45 days