Question

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8v^2+37v=0 (solve)
solve a quadratic equation (topic)

Answer 1

Solving the quadratic equation
`8v^2+37v=0` we get:
`\mathbf{v=0\:or\:v=(-37)/(8)}`

Explanation:

We need to solve the quadratic equation:
`8v^2+37v=0`

We can solve the quadratic equation of form
`ax^2+bx+c=0` using quadratic formula:
`x=(-b\pm√(b^2-4ac))/(2a)`

We need to put values of a , b and c in order to find the solutions of quadratic equations.

In the given equation:
`8v^2+37v=0` we have, a =8, b=37, c=0

Putting values and finding the values for n:

`v=(-b\pm√(b^2-4ac))/(2a)\\v=(-37\pm√((-37)^2-4(8)(0)))/(2(8))\\v=(-37\pm√((-37)^2-0))/(2(8))\\v=(-37\pm√(1369))/(2(8))\\v=(-37\pm37)/(2(8))\\v=(-37+37)/(2(8))\:or\:v=(-37-37)/(2(8))\\v=(0)/(2(8))\:or\:v=(-74)/(2(8))\\v=0\:or\:v=(-37)/(8)`

So, solving the quadratic equation
`8v^2+37v=0` we get:
`\mathbf{v=0\:or\:v=(-37)/(8)}`