Question

Write in standard form
y=1/3(x+6)^2-9

Answer 1

`y=(1)/(3)x^2+4x+3`

Explanation:

we know that

The standard form of a quadratic equation is equal to

`ax^(2) +bx+c`

we have

`y=(1)/(3)(x+6)^2-9`

This is the equation of a vertical parabola written in vertex form

Expanded the quadratic equation

`y=(1)/(3)(x^2+12x+36)-9`

Apply distributive property right side

`y=(1)/(3)x^2+4x+12-9`

`y=(1)/(3)x^2+4x+3` ---> quadratic equation in standard form