Question

For the reaction

6Li+ N2 —> 2Li3N

What us the maximum amount of Li3B which could be formed from 7.87 mol of Li and 4.37 mol of N2?

Answer in units of mol.

Answer 1

Mass = 90.6 g

2.6 mol

Step-by-step explanation:

Given data:

Number of moles of Li = 7.87 mol

Number of moles of N = 4.37 mol

Mass of Li₃N = ?

Solution

Chemical equation:

6Li + N₂ → 2Li₃N

Now we will compare the moles of nitrogen and lithium with Li₃N.

N₂ : Li₃N

1 : 2

4.37 : 2×4.37 =8.74

Li : Li₃N

6 : 2

7.87 : 2/6×7.87 = 2.6 mol

Mass of Li₃N:

Mass = number of moles × molar mass

Mass = 2.6 mol × 34.83 g/mol

Mass = 90.6 g