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2x^2+4x-3=0
please show steps ​

1 Answer

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Step 1) Multiply 2x^2 by -3

2x^2+4x-6x-3

Step 2) Place in parentheses

(2x^2+4x) - (6x-3)

Step 3) Find out everything you can take out in each parentheses.

**In (2x^2+4x), you can take out 2x because each number has an x and 2 is the largest number that can go into 2 and 4.**

**In (6x-3), you can take out a 3.**

2x(x+2) + 3(x+2) <<< this is how it should look before the final answer.

Step 4) You would know when you did each step correctly when the numbers in the parentheses match exactly.

Final answer: (2x-3)(x+2)

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User Keshon
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