Question

A small crack occurs at the base of a 15.0-m-high dam. The effective area through which water leaves is 2.30 × 10-3 m2. (a) Ignoring viscous losses, what is the speed of water flowing through the crack? (b) How many cubic meters per second of water leave the dam?

Answer 1

given,

height of the dam = 15 m

effective area of water = 2.3 x 10⁻³ m²

Using energy conservation

`m g h = (1)/(2)mv^2`

`v= √(2gh)`

`v= √(2* 9.8 * 15)`

`v= √(294)`

v = 17.15 m/s

discharge of water

Q = A V

Q = 2.3 x 10⁻³ x 17.15

Q = 0.039 m³/s