Question

The free energy change ΔGT at 2400 K is equal to 1.22 x 10^5J/mol. Calculate the equilibrium constant at 2400 K. Express your answer numerically.

Answer 1

K = 2.21 × 10⁻³

Step-by-step explanation:

The Gibbs free energy change (ΔG°) at a temperature T = 2400 K is 1.22 × 10⁵ J/mol. We can calculate the equilibrium constant (K) using the following expression.

`\Delta G\°=-R.T.lnK`

where,

R is the ideal gas constant (8.314 J/mol.K)

T is the absolute temperature

`\Delta G\°=-R.T.lnK\\lnK=(-\Delta G\°)/(R.T) =(-1.22 * 10^(5)J/mol)/((8.314J/K.mol).2400K) \\K=2.21 * 10^(-3)`