Question

What is an equation for the line that passes through points (8.-3) and (9, 10)?

Answer 1

y+3=13(x-8)

Explanation:

y-y1=m(x-x1)

m=(y2-y1)/(x2-x1)

m=(10-(-3))/(9-8)

m=(10+3)/1

m=13/1

m=13

y-(-3)=13(x-8)

y+3=13(x-8)