Calculate the work, w, gained or lost by the system when a gas expands from 15 L to 45 L against a constant external pressure of 1.5 atm. 1 L × atm = 101 J.

Question

asked Feb 7, 2020 230k views

1 Answer

Khadreal · Answer 1 · 2020-02-14T02:42:16+0000

Answer:

Work done by the system = 4545 J

Step-by-step explanation:

The expression for the calculation of work done is shown below as:

$w=-P* \Delta V$

Where, P is the pressure

$\Delta V$ is the change in volume

From the question,

$\Delta V$ = 45 - 15 L = 30 L

P = 1.5 atm

$w=-1.5* 30\ atmL$

Also, 1 atmL = 101 J

So,

$w=-1.0*0.75* 101\ J=-4545\ J$ (negative sign implies work is done by the system)

Work done by the system = 4545 J