Question

Pls help is due for today pls

Answer 1

Part A: The rate of change was greater in case of the graph.

Part B: The figure shows the graph of function A in Redline and Function B in blue line

Part C : Initial value of function B is greater than Function A.

Explanation:

Here, Function A show graph of a line and Function show table show a set of value of x and y.

Part A). Which function show greater rate of change.

The slope of line is given by m =
`(Y2-Y1)/(X2-X1)`

For function A:

Given graph passes through points (04) and (2,12)

The slope of line is m=
`(12-4)/(2-0)`

=
`(8)/(2)`

= 4

For function B:

Given the table has points (012) and (2,14)

The slope of line is m=
`(14-12)/(2-0)`

=
`(2)/(2)`

= 1

Therefore, The rate of change was greater in case of graph.

Part B). Plot the graph of a function B onto the graph of a function A

The figure shows the graph of function A in Redline and Function B in blueline

Line of function A is more tilted toward the y-axis than Line of function B.

Therefore, Rate of change of function A is greater than Function B.

Part C). Which function has greater initial value?

For function A:

From the graph of part B,

When x=0 y=4

For function B:

From the graph of part B,

When x=0 y=12

Therefore, Initial value of function B is greater than Function A.