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3x^2 – 12x – 2y - 2 = 0 -3y^2 – 22y - 19 = 3x^2 – 12x

3x^2 – 12x – 2y - 2 = 0 -3y^2 – 22y - 19 = 3x^2 – 12x
asked 152k views
5 votes
3x^2 – 12x – 2y - 2 = 0
-3y^2 – 22y - 19 = 3x^2 – 12x

asked
User Akshay Misal
by
7.5k points

1 Answer

4 votes

Answer:

x

=

0

,

y

=

−

1

x

=

4

,

y

=

−

1

x

=

2

,

y

=

−

7

Explanation:

answered
User Deepak Gunasekaran
by
8.5k points
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