Question

Kevin is 333 years older than Daniel. Two years ago, Kevin was 444 times as old as Daniel.

Let kkk be Kevin's age and let ddd be Daniel's age.
Which system of equations represents this situation?

Answer 1

k=d+3

k−2=4(d−2)

Answer 2

Answer:
`k= d+3`

`k-2 = 4(d-2)`

Explanation:

Let k be Kevin's age and Let d be Daniel's age.

Given : Kevin is 3 years older than Daniel.

i.e. Age of Kelvin = Age of Daniel+ 3

i.e. In terms of variables , k= d+3 (1)

Two years ago,

Age of Kelvin = k-2

Age of Daniel = d-2

Since Two years ago ,Kevin was 4 times as old as Daniel.

i.e. In terms of variables :
`k-2 = 4*(d-2)`

`k-2 = 4(d-2)` (2)

From (1) and (2) the system of equations represents this situation are

`k= d+3`

`k-2 = 4(d-2)`