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Please help with this simple trig problem- angle of two sectors of a circle

Please help with this simple trig problem- angle of two sectors of a circle-example-1

1 Answer

3 votes

Answer:

K = (1/2)r^2(sin(θ) +θ)

Explanation:

The area of the triangle to the left is ...

A1 = (1/2)r^2·sin(180°-θ) = (1/2)r^2·sin(θ)

The area of the sector to the right is ...

A2 = (1/2)r^2θ

so the total area of the blue shaded region is ...

K = A1 + A2 = (1/2)r^2·sin(θ) + (1/2)r^2·θ

K = (1/2)r^2(sin(θ) +θ)

answered
User Sterling Nichols
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