Question

Calculate the volume in liters of a 0.00231M copper(II) fluoride solution that contains 175.g of copper(II) fluoride CuF2. Be sure your answer has the correct number of significant digits.

Answer 1

Volume = 746 L

Step-by-step explanation:

Given that:- Mass of copper(II) fluoride = 175 g

Molar mass of copper(II) fluoride = 101.543 g/mol

The formula for the calculation of moles is shown below:

`moles = (Mass\ taken)/(Molar\ mass)`

Thus,

`Moles= (175\ g)/(101.543\ g/mol)`

`Moles_(copper(II)\ fluoride)= 1.7234\ mol`

Also,

Considering:

`Molarity=(Moles\ of\ solute)/(Volume\ of\ the\ solution)`

So,,

`Volume =(Moles\ of\ solute)/(Molarity)`

Given, Molarity = 0.00231 M

So,

`Volume =(1.7234)/(0.00231)\ L`

Volume = 746 L