An iron anchor of density 7850.00 kg/m3 appears 183 N lighter in water than in air. a. What is the volume of the anchor? b. How much does it weigh in the air?

Question

asked Apr 24, 2020 221k views

1 Answer

Zenuka · Answer 1 · 2020-04-29T21:04:08+0000

Step-by-step explanation:

a) Weight loss in water = Volume of object x density of water x acceleration due to gravity

183 = Volume of anchor x 1000 x 9.81

Volume of anchor = 0.019 m³

b) Weight = Mass x acceleration due to gravity = Volume x Density x acceleration due to gravity

Weight of anchor in air = Volume of anchor x Density of anchor x acceleration due to gravity

Weight of anchor in air = 0.019 x 7850 x 9.81 = 1463.17 N

Weight of anchor in air = 1463.17 N