Question

. How many moles of 58.6L of Nitrogen gas N2 at STP

Answer 1

n = 2.62 mol

Step-by-step explanation:

Given data:

Volume of nitrogen = 58.6 L

Temperature = 273 K

Pressure = 1 atm

Number of moles = ?

Solution;

PV = nRT

n = PV / RT

n = 1 atm. 58.6 L / 0.0821 atm. L/mol. K × 273 K

n = 58.6 L. atm / 22.4 atm. L/mol.

n = 2.62 mol