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In moving out of a dormitory at the end of the semester, a student does1.6×10^4Jof work. In the process, his internal energy decreases by4.2×10^4JDetermine each of the following quantities (including the algebraic sign):(a)W,(b)ΔU, and (c)Q

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User Kingkong
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1 Answer

3 votes

Answer:

W = 1.6 × 10⁴ J , ΔU = - 4.2 x 10⁴ J , Q = - 2.6 x 10⁴ J

Step-by-step explanation:

given,

Work done by the student

W = 1.6 × 10⁴ J

decrease in internal energy

ΔU = - 4.2 x 10⁴ J

Using formula for heat

Q = W + ΔU

Q = 1.6 × 10⁴ J + ( - 4.2 x 10⁴ J)

Q = - 2.6 x 10⁴ J

Hence,

W = 1.6 × 10⁴ J , ΔU = - 4.2 x 10⁴ J , Q = - 2.6 x 10⁴ J

answered
User Don Jewett
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8.8k points

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