How many moles of N2O5 are needed to produce 7.90 g of NO2?

Question

asked Oct 9, 2020 81.3k views

2 Answers

Ulysses · Answer 1 · 2020-10-09T13:43:23+0000

Answer:

0.13 mole

Step-by-step explanation:

Mole of N2O5 = 0.26 mole x 1/2 = 0.13 mole. So, 0.13 mole of N2O5 is needed to produce 7.90 g NO2