Question

Picture attached below

Answer 1

b

Explanation:

Using the trigonometric identity

secx =
`(1)/(cosx)` and cos60° =
`(1)/(2)`

Given

sec [
`sin^(-1)`
`(√(3) )/(2)` ] ← evaluate bracket

= sec60°

=
`(1)/(cos60)`

=
`(1)/((1)/(2) )`

= 2 → b