Question

A particular planet has a moment of inertia of 8.26 × 1036 kg⋅m2 and a mass of 6.54 × 1022 kg. Based on these values, what is the planet's radius? Hint: Because planets are the shape of a sphere, the moment of inertia is I = (2/5)mr2.

7.12 × 106 m
1.78 × 107 m
5.05 × 1013 m
3.16 × 1014

Answer 1

1.78 x 10^7 m

Step-by-step explanation:

Answer 2

Answer: Correct answer is B = 1.776933×
`10^(7)`

Explanation:

Given :

Moment of inertia I = 8.26×
`10^(36)` kg
`m^(2)`

Mass of planet m = 6.54×
`10^(22)` kg

Also, Planet is solid sphere so that, Moment of inertia is I =
`(2)/(5)` m
`R^(2)` =0.4m
`R^(2)`

Where R is radius of planet

Putting into calculation

We get,

I =
`(2)/(5)` m
`R^(2)`

8.26×
`10^(36)` = 0.4×6.54×
`10^(22)`×
`R^(2)`

8.26×
`10^(14)` = 2.616
`R^(2)`

3.15749235×
`10^(14)` =
`R^(2)`

R = 1.776933×
`10^(7)`

Thus, Correct answer is B = 1.776933×
`10^(7)`