Question

A sample of hydrogen gas has an initial pressure of 2.86 atm and an initial volume of 8472 mL If the volume of the

were decreased to 365.8 ml, what would the new pressure be? Gas Law used:

Answer 1

Gas law : Boyle's law

New pressure: 66.24 atm

Step-by-step explanation:

Concept tested: Gas laws (Boyle's law)

We are given,

• Initial pressure, P₁ = 2.86 atm
• Initial volume, V₁ = 8472 mL
• New volume, V₂ IS 365.8 mL

We need to determine the new pressure, P₂

• According to Boyle's law , the volume of a fixed mass of a gas and the pressure are inversely proportional at constant temperature.

• That is,
  `P\alpha (1)/(V)`
• This means , PV = k (constant)
• Therefore; P₁V₁ = P₂V₂

• Rearranging the formula, we can get the new pressure, P₂

P₂ = P₁V₁ ÷ V₂

= (2.86 atm × 8472 mL) ÷ 365.8 mL

= 66.24 atm

Therefore, the new pressure is 66.24 atm