Question

Helpppppppp me plzzzzzzzz

Answer 1

A

Explanation:

Using the rules of exponents

`a^(m)` ×
`a^(n)` ⇔
`a^((m+n))`

`a^(-m)` =
`(1)/(a^(m) )`

Given

`3^{(2)/(5) }` ×
`3^{-(7)/(5) }`

=
`3^{(2)/(5)-(7)/(5)  }`

=
`3^{-(5)/(5) }`

=
`3^(-1)`

=
`(1)/(3)` → A