Question

What is the pOH of a 0.0092 M CsOH solution?

A) 2.04
B) 16.04
C) 9.31
D) 4.69
E) 11.96

Answer 1

2.04 is the pOH of a 0.0092 M CsOH solution.

Step-by-step explanation:

Molarity of cesium hydroxde = [CsOH]= 0.0092

`CsOH(aq)\rightarrow Cs^+(aq)+OH^-(aq)`

1 mole of cesium hydroxide gives 1 mole of cesium ion and 1 mole of hydroxide ion.

Then 0.0092 M cesium hydroxide will give :

`[OH^-]=1* [CsOH]=1* 0.0092 M=0.0092M`

The pOH of the solution is the negative logarithm of concentration of hydroxide ions in a solution.

`pOH=-\log [OH^-]`

`pOH=-\log [0.0092 M]=2.0362\approx 2.04`

2.04 is the pOH of a 0.0092 M CsOH solution.