Question

Dolphins emit clicks of sound for communication and echolocation. A marine biologist is monitoring a dolphin swimming in seawater where the speed of sound is 1522 m/s. When the dolphin is swimming directly away at 7.2 m/s, the marine biologist measures the number of clicks occurring per second to be at a frequency of 2674 Hz. What is the difference (in Hz) between this frequency and the number of clicks per second actually emitted by the dolphin?

Answer 1

12.64968 Hz

Step-by-step explanation:

v = Velocity of sound in seawater = 1522 m/s

u = Velocity of dolphin = 7.2 m/s

f' = Actual frequency = 2674 Hz

From Doppler effect we get the relation

`f=f'(v-u)/(v)\\\Rightarrow f=2674(1522-7.2)/(1522)\\\Rightarrow f=2661.35032\ Hz`

The frequency that will be received is 2661.35032 Hz

The difference in the frequency will be

`2674-2661.35032=12.64968\ Hz`