Question

the brakes applied to a car produces an acceleration of 6m/s^2 in the opposite direction to the motion. if the car takes 2s to stop after the application of brakes. calculate the distance it travels during this time .

Answer 1

acceleration= -6ms^-2

Step-by-step explanation:

`v = u + at \\ 0 = u + ( - 6 * 2) \\ u = 12m {s}^( - 1)`

distance

`s = ut + (1)/(2) a {t}^(2) \\ s = 12 * 2 + (1)/(2) * ( - 6) * {2}^(2) \\ s = 12m`

therefore distance = 12m