Question

Given the following cross between parents of the genotypes AABBCc × AabbCc, assume simple dominance for each trait and independent assortment. What proportion of the progeny will be expected to phenotypically resemble the first parent?

Answer 1

3/4

Step-by-step explanation:

The first parent with the "AABBCc" genotype would express the dominant trait for all the three loci since the mentioned loci exhibit simple dominance for each trait and independent assortment. Therefore, the desired progeny should also exhibit the dominant trait for all three loci.

Parents= AABBCc × AabbCc

AA x Aa= 1/2 AA (dominant): 1/2 Aa (dominant) = 100% dominant progeny

BB x bb = Bb (dominant) = 100% dominant progeny

Cc x Cc = 1/4 CC (dominant): 1/2 Cc (dominant): 1/4 cc (recessive) = 3/4 dominant : 1/4 recessive progeny

Therefore, the proportion of the progeny showing the dominant trait for all the three loci= 1 x 1 x 3/4 = 3/4