Question

Two long parallel wires, each carrying a current of 12 A, lie at a distance of 9 cm from each other. What is the magnetic force per unit length exerted by one wire on the other? The magnetic force per unit length exerted by one wire on the other is ×10-4 N/m.

Answer 1

Force per unit length between two conductors will be
`3.2* 10^(-4)N`

Step-by-step explanation:

We have given that two long parallel wires each carrying a current of 12 A

So
`I_1=I_2=12A`

Distance between the two conductors d = 9 cm = 0.09 m

We know that magnetic force between two parallel conductors per unit length is given by

`F=(\mu _0I_1I_2)/(2\pi d)=(4* 3.14* 10^(-7)* 12* 12)/(2* 3.14* 0.09)=3.2* 10^(-4)N`

Force per unit length between two conductors will be
`3.2* 10^(-4)N`