Question

When responding to sound, the human eardrum vibrates about its equilibrium position. Suppose an eardrum is vibrating with an amplitude of 5.70 10-7 m and a maximum speed of 2.66 10-3 m/s. (a) What is the frequency (in Hz) of the eardrum's vibration

Answer 1

Frequency will be 743.09 Hz

Step-by-step explanation:

We have given maximum speed
`v_m=2.66* 10^(-3)m/sec`

Amplitude
`A=5.7* 10^(-7)m`

We have to find the frequency of the vibration

We know that angular frequency is given by

`\omega =(v_m)/(A)=(2.66* 10^(-3))/(5.7* 10^(-7))=4666.666rad/sec`

`2\pi f=4666.66`

`f=743.09Hz`