Answer:
9 and 23
Explanation:
You can adjust the problem a little bit and make it easier to solve.
Subtracting 5 from the larger number makes it twice the smaller, and their sum be 32-5 = 27. So 27 is 3 times the smaller number, 9, and the larger is 32-9 = 23, which is 5 more than two times 9.
The two numbers are 9 and 23.
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You can let x represent "the other number". Then "one number" is 2x+5, and their sum is ...
(x) +(2x+5) = 32
3x +5 = 32
3x = 27 . . . . . subtract 5
x = 9 . . . . . . . divide by 3
(This working out should look familiar if you followed the above verbal solution.)
"One number" is 27 and "the other number" is 9.