asked 121k views
4 votes
The equation
2m^(2)-1m-8=0 has solutions of the form

M= N +or- sqaure root of D/over M


Solve this equation and find the appropriate values of N,M,and D. Do not worry about simplifying the √D portion of the solution.


N= M= D=

1 Answer

2 votes

Answer:

  • N = 1
  • M = 4
  • D = 65

Explanation:

The given equation is of the form ...

ax² +bx +c = 0

where a=2, b=-1, c=-8.

The quadratic formula gives the solution to the above equation as ...


x=(-b\pm√(b^2-4ac))/(2a)

So, for your equation, the solution is ...


m=(-(-1)\pm√((-1)^2-4(2)(-8)))/(2(2))=(1\pm√(65))/(4)

Comparing this to the form ...


m=(N\pm√(D))/(M)

we see ...

  • N = 1
  • M = 4
  • D = 65
answered
User Oleg Melnikov
by
7.9k points
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