Question

Write an equation in point slope form line passing through (-4,3), (3,-4)
SHOW WORK

Answer 1

`\large\boxed{y-3=-(x+4)}\\or\\\boxed{y+4=-(x-3)}`

Explanation:

The point-slope form of an equation of a line:

`y-y_1=m(x-x_1)`

m - slope

(x₁, y₁) - point on a line

The formula of a slope:

`m=(y_2-y_1)/(x_2-x_1)`

We have two points (-4, 3) and (3, -4).

Substitute:

`m=(-4-3)/(3-(-4))=(-7)/(7)=-1`

Put the value of a slope and the coordiantes of the point (-4, 3) or (3, -4) to the equation of a line:

for (-4, 3)

`y-3=-1(x-(-4))\\\\y-3=-(x+4)`

for (3, -4)

`y-(-4)=-1(x-3)\\\\y+4=-(x-3)`