Question

A radio wave transmits 36.8 W/m2 of power per unit area. A flat surface of area A is perpendicular to the direction of propagation of the wave. Assuming the surface is a perfect absorber, calculate the radiation pressure on it.

Answer 1

122.6 nPa

Step-by-step explanation:

Here ,

Intensity of incident light , I = 36.8 W/m^2

angle with area, θ = 0 degree

for a perfect absorber ,

radiation pressure =
`(Icos\theta)/(c)`

I= Intensity of incident light, c= speed of light

radiation pressure =
`(36.8* cos0)/(3*10^8)`

radiation pressure = 12.26×10^-8 Pa

radiation pressure = 122.6 nPa

the radiation pressure acting on the 122.6 nPa