Question

A student whirls a rubber stopper attached to a string in a horizontal circle above her head. If the radius of the stopper in circular motion is a constant 50.00 cm, and the time it takes the stopper to make one full revolution is 0.2500 seconds, what is the tangential speed of the stopper?

Answer 1

`v = 12.57 m/s`

Step-by-step explanation:

As we know that the radius of the circular motion is given as

`R = 50.00 cm`

time period of the motion is given as

`T = 0.2500 s`

now we know that it is moving with uniform speed

so it is given as

`v = (2\pi R)/(T)`

now plug in all data

`v = (2\pi(0.50))/(0.25)`

`v = 12.57 m/s`