Question

A large fraction of the ultraviolet (UV) radiation coming from the sun is absorbed by the atmosphere. The main UV absorber in our atmosphere is ozone, O3. In particular, ozone absorbs radiation with frequencies around 9.38×1014 Hz . What is the wavelength λ of the radiation absorbed by ozone?

Answer 1

Answer : The wavelength of the radiation absorbed by ozone is,
`3.20* 10^(-7)m`

Explanation : Given,

Frequency =
`9.38* 10^(14)Hz=9.38* 10^(14)s^(-1)`

Formula used :

`\\u=(c)/(\lambda)`

where,

`\\u` = frequency

`\lambda` = wavelength

c = speed of light =
`3* 10^8m/s`

Now put all the given values in the above formula, we get:

`9.38* 10^(14)s^(-1)=(3* 10^8m/s)/(\lambda)`

`\lambda=3.20* 10^(-7)m`

Therefore, the wavelength of the radiation absorbed by ozone is,
`3.20* 10^(-7)m`

Answer 2

`\lambda=3.20*10^(-7)m`

Step-by-step explanation:

The wavelength is inversely proportional to the frequency. The wavelength is equal to the speed of the wave, divided by the frequency. In the case of electromagnetic waves like ultraviolet radiation, the speed of propagation is the speed of light.

`\lambda=(c)/(f)\\\lambda=(3*10^8(m)/(s))/(9.38*10^(14)Hz)\\\lambda=3.20*10^(-7)m`