Question

84. Heavy water, D2O (molar mass = 20.03 g mol–1), can be separated from ordinary water, H2O (molar mass = 18.01), as a result of the difference in the relative rates of diffusion of the molecules in the gas phase. Calculate the relative rates of diffusion of H2O and D2O.

Answer 1

relative rate of diffusion is 1.05

Step-by-step explanation:

According to Graham's law of difussion:

Rate of diffusion is inversely proportional to the square root of molecular weight of a molecule.

For two given molecules:

`((rate)_(1))/((rate)_(2))=\frac{\sqrt{M_(2)} }{\sqrt{M_(1)}}`

The given molecules are

Water = 18.01

Heavy water =20.03

Thus the relative rate of diffusion will be:

`((rate)_(water))/((rate)_(heavywater))=\sqrt{ (20.03)/(18.01)}=1.05`