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Draw all of the monochlorination products that you might obtain from the free-radical chlorination of ethylcyclopropane.You do not have to consider stereochemistry.Draw one structure per sketcher. Add additional sketchers using the dropdown menu in the bottom right corner.Separate multiple products using the + sign from the dropdown menu.

asked
User LShi
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1 Answer

6 votes

Answer:

-) (2-chloroethyl)cyclopropane

-) (1-chloroethyl)cyclopropane

-) 1-chloro-2-ethylcyclopropane

-) 1-chloro-1-ethylcyclopropane

Step-by-step explanation:

The monochlorination are products in which Cl is added only 1 time. Now, in the ethylcyclopropane we will have 5 carbons, so we will have 5 options for monochlorination (see figure 1). But, for carbons 2 and 3 we will have equivalent structures, therefore at the end, we will have only 4 possible structures. In carbon 5, carbon 4, carbon 3 and carbon 1 (see figure 2).

Draw all of the monochlorination products that you might obtain from the free-radical-example-1
Draw all of the monochlorination products that you might obtain from the free-radical-example-2
answered
User MidnightGun
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7.8k points
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