Question

A 41.0 kg child swings in a swing supported by two chains, each 2.98 m long. (a) If the tension in each chain at the lowest point is 348 N, find the child's speed at the lowest point. m/s (b) What is the force exerted by the seat on the child at the lowest point? (Neglect the mass of the seat.) N (upward)

Answer 1

Answer:695.5 N

Step-by-step explanation:

mass of child
`m=41 kg`

Length of chain
`L=2.98 m`

Tension in each chain
`T=348 N`

(a)Tension at bottom point
`T=348 N`

At lowest Point

`T+T-mg=(mv^2)/(L)`

`2T-mg=(mv^2)/(L)`

`2* 348-41* 9.8=(41* v^2)/(2.98)`

`v^2=(294.2* 2.98)/(41)`

`v=√(21.38)=4.62 m/s`

(b)Force exerted by Seat will be Equal to Normal reaction

`N-mg=(mv^2)/(L)`

`N=mg+(mv^2)/(L)`

`N=41* 9.8+(41* 21.38)/(2.98)`

`N=695.95 N`