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A poll showed that 48 out of 120 randomly chosen graduates of California medical schools last year intended to specialize in family practice. What is the margin of error for a 9…

A poll showed that 48 out of 120 randomly chosen graduates of California medical schools last year intended to specialize in family practice. What is the margin of error for a 9…
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A poll showed that 48 out of 120 randomly chosen graduates of California medical schools last year intended to specialize in family practice. What is the margin of error for a 90 percent confidence interval for the proportion that plan to specialize in family practice?

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User Matteofigus
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8.5k points

1 Answer

4 votes

Answer:

+-4.8

Explanation:

4.8 is 10% of 48, so it can up or down by that much.

answered
User Manngo
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7.6k points
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