Question

You throw a 50.0g blob of clay directly at the wall with an initial velocity of -5.00 m/s i. The clay sticks to the wall, and the collision takes about 20.0 ms (2.00 x 10^-2 s). a) What is the change in momentum for the blob of clay?

Answer 1

Answer:0.25 kg-m/s

Step-by-step explanation:

Given

mass of blob
`m=50 gm`

initial velocity
`u=-5 m/s\ \hat{i}`

time of collision
`t=20 ms`

we know Impulse is equal to change in momentum

initial momentum
`P_i=mu`

`P_i=50* 10^(-3)* (-5)=-0.25 kg-m/s`

Final momentum
`P_f=50* 10^(-3)v`

`P_f=0` as final velocity is zero

Impulse
`J=P_f-P_i`

`J=0-(-0.25)`

`J=0.25 kg-m/s`