Answer:
3/2 < x < 2
Explanation:
We assume the problem is ...
[tek]\dfrac{1}{x-2}<-2[/tex]
This will not be true for x-2 > 0 because that would make the left side positive. So, we must have x < 2, which makes the denominator negative. Multiplying by (x-2), we get ...
1 > -2(x -2)
1 > -2x +4
2x > 3 . . . . . . add 2x-1
x > 3/2
From above, we also have x < 2, so the solution set is ...
3/2 < x < 2